The C# DateTime objects have a anycodings_javascript Kind property, but no strict underlying anycodings_javascript time zone as such, and time zone anycodings_javascript conversions are difficult to track if anycodings_javascript you are converting between two non UTC anycodings_javascript and non local times. I actually think Date values in js are anycodings_javascript far better than say the C# DateTime anycodings_javascript objects. This is anycodings_javascript because getUTCDate() returns the day of anycodings_javascript the month whereas, getUTCDay() returns anycodings_javascript the day of the week. "Sun, 03:50:34 GMT" // four hours less than my local time, and two hours less than the original time - because my GMT+2 input was interpreted as GMT+0!Īlso note that getUTCDate() cannot be anycodings_javascript substituted for getUTCDay(). > var d2 = new Date( d1.getUTCFullYear(), d1.getUTCMonth(), d1.getUTCDate(), d1.getUTCHours(), d1.getUTCMinutes(), d1.getUTCSeconds() ) "Sun, 05:50:34 GMT" // two hours less than my local time Observe (I'm in GMT +02:00 right anycodings_javascript now, and it's 07:50): > var d1 = new Date() If anycodings_javascript UTC time is passed in, the results will anycodings_javascript differ. For a string anycodings_javascript representation, David Ellis' answer anycodings_javascript works.
It will factor the current timezone anycodings_javascript offset into the result. Note that getTime() returns anycodings_javascript milliseconds, not plain seconds.įor a UTC/Unix timestamp, the following anycodings_javascript should suffice: Math.floor((new Date()).getTime() / 1000)
Get utc time javascript android#
(I had problems getting that anycodings_javascript to work in an older Android browser.) To set the timezone of a anycodings_javascript certain date object is to construct it anycodings_javascript from a date string that includes the anycodings_javascript timezone.
Dates constructed that way use the local anycodings_javascript timezone, making the constructed date anycodings_javascript incorrect.
0 kommentar(er)
